\begin{equation} (a+b)^{2} = a^{2}+2ab+b^{2} \end{equation}
\begin{equation} x=\frac{-b+-\sqrt{b^{2}-4ac}}{2a} \end{equation}
\begin{equation} x=\frac{-b\pm\sqrt{b^{2}-4ac}}{2a} \end{equation}
\begin{equation} = (k+1)n + \frac{k(k+1)}{2} = \frac{(k+1)(2n+k)}{2} \end{equation}
\begin{equation} (2)^{10} = 1024 \end{equation}
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aashamsakal.......... blogil puthiya post..... PRITHVIRAJINE PRANAYICHA PENKUTTY.......... vayikkane..........
[im]https://sites.google.com/site/classroommaths/hexagon-squ/10.jpeg?attredirects=0&d=1[/im]
a^{2} ഒരു പൂര്ണ്ണവര്ഗ്ഗമാണെങ്കില് (a\pm(d))^{2 }ഒരു പൂര്ണ്ണവര്ഗ്ഗമായിരിക്കും.
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\begin{equation} (a+b)^{2} = a^{2}+2ab+b^{2} \end{equation}
\begin{equation} x=\frac{-b+-\sqrt{b^{2}-4ac}}{2a} \end{equation}
\begin{equation} x=\frac{-b\pm\sqrt{b^{2}-4ac}}{2a} \end{equation}
\begin{equation} = (k+1)n + \frac{k(k+1)}{2} = \frac{(k+1)(2n+k)}{2} \end{equation}
\begin{equation} (2)^{10} = 1024 \end{equation}
\textit{ Italic }
aashamsakal.......... blogil puthiya post..... PRITHVIRAJINE PRANAYICHA PENKUTTY.......... vayikkane..........
[im]https://sites.google.com/site/classroommaths/hexagon-squ/10.jpeg?attredirects=0&d=1[/im]
a^{2} ഒരു പൂര്ണ്ണവര്ഗ്ഗമാണെങ്കില് (a\pm(d))^{2 }ഒരു പൂര്ണ്ണവര്ഗ്ഗമായിരിക്കും.
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